3243142423 has 4 divisors (see below), whose sum is σ = 3243930120. Its totient is φ = 3242354728.

The previous prime is 3243142391. The next prime is 3243142447. The reversal of 3243142423 is 3242413423.

3243142423 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 3243142423 - 2⁵ = 3243142391 is a prime.

It is a super-3 number, since 3×3243142423³ (a number of 30 digits) contains 333 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 3243142391 and 3243142400.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (3243142723) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 387640 + ... + 395917.

It is an arithmetic number, because the mean of its divisors is an integer number (810982530).

Almost surely, 2^3243142423 is an apocalyptic number.

3243142423 is a deficient number, since it is larger than the sum of its proper divisors (787697).

3243142423 is an equidigital number, since it uses as much as digits as its factorization.

3243142423 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 787696.

The product of its digits is 13824, while the sum is 28.

The square root of 3243142423 is about 56948.5945656256. The cubic root of 3243142423 is about 1480.2054777711.

Adding to 3243142423 its reverse (3242413423), we get a palindrome (6485555846).

Subtracting from 3243142423 its reverse (3242413423), we obtain a cube (729000 = 90³).

The spelling of 3243142423 in words is "three billion, two hundred forty-three million, one hundred forty-two thousand, four hundred twenty-three".