Base | Representation |
---|---|
bin | 101111010010010011010… |
… | …101001111110101010001 |
3 | 102111122102221121211021001 |
4 | 233102103111033311101 |
5 | 411214402034041101 |
6 | 10524441245102001 |
7 | 453523552406041 |
oct | 57222325176521 |
9 | 12448387554231 |
10 | 3249467096401 |
11 | 104310050a629 |
12 | 445927b57901 |
13 | 1a7567386206 |
14 | b33bca29721 |
15 | 597d5895901 |
hex | 2f49354fd51 |
3249467096401 has 2 divisors, whose sum is σ = 3249467096402. Its totient is φ = 3249467096400.
The previous prime is 3249467096383. The next prime is 3249467096429. The reversal of 3249467096401 is 1046907649423.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 3133169045776 + 116298050625 = 1770076^2 + 341025^2 .
It is a cyclic number.
It is not a de Polignac number, because 3249467096401 - 211 = 3249467094353 is a prime.
It is not a weakly prime, because it can be changed into another prime (3249467096431) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1624733548200 + 1624733548201.
It is an arithmetic number, because the mean of its divisors is an integer number (1624733548201).
Almost surely, 23249467096401 is an apocalyptic number.
It is an amenable number.
3249467096401 is a deficient number, since it is larger than the sum of its proper divisors (1).
3249467096401 is an equidigital number, since it uses as much as digits as its factorization.
3249467096401 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 7838208, while the sum is 55.
The spelling of 3249467096401 in words is "three trillion, two hundred forty-nine billion, four hundred sixty-seven million, ninety-six thousand, four hundred one".
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