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324994006553 is a prime number
BaseRepresentation
bin1001011101010110010…
…01101111111000011001
31011001212101120010002112
410232223021233320121
520311041431202203
6405144501242105
732323440322166
oct4565311577031
91131771503075
10324994006553
1111591370a367
1252b9ba03335
13248540470b8
1411a307a906d
1586c1a9a6d8
hex4bab26fe19

324994006553 has 2 divisors, whose sum is σ = 324994006554. Its totient is φ = 324994006552.

The previous prime is 324994006537. The next prime is 324994006613. The reversal of 324994006553 is 355600499423.

It is a happy number.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 297622620304 + 27371386249 = 545548^2 + 165443^2 .

It is a cyclic number.

It is not a de Polignac number, because 324994006553 - 24 = 324994006537 is a prime.

It is a super-2 number, since 2×3249940065532 (a number of 24 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (324994006523) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 162497003276 + 162497003277.

It is an arithmetic number, because the mean of its divisors is an integer number (162497003277).

Almost surely, 2324994006553 is an apocalyptic number.

It is an amenable number.

324994006553 is a deficient number, since it is larger than the sum of its proper divisors (1).

324994006553 is an equidigital number, since it uses as much as digits as its factorization.

324994006553 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 3499200, while the sum is 50.

The spelling of 324994006553 in words is "three hundred twenty-four billion, nine hundred ninety-four million, six thousand, five hundred fifty-three".