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3250101315 = 35216673421
BaseRepresentation
bin1100000110111000…
…1001110001000011
322101111122020211210
43001232021301003
523124011220230
61254300541203
7143353256016
oct30156116103
98344566753
103250101315
11141866324a
12768551803
133ca461096
1422b90b37d
151404e7eb0
hexc1b89c43

3250101315 has 8 divisors (see below), whose sum is σ = 5200162128. Its totient is φ = 1733387360.

The previous prime is 3250101299. The next prime is 3250101343. The reversal of 3250101315 is 5131010523.

It is a sphenic number, since it is the product of 3 distinct primes.

It is not a de Polignac number, because 3250101315 - 24 = 3250101299 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 3250101291 and 3250101300.

It is an unprimeable number.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 108336696 + ... + 108336725.

It is an arithmetic number, because the mean of its divisors is an integer number (650020266).

Almost surely, 23250101315 is an apocalyptic number.

3250101315 is a deficient number, since it is larger than the sum of its proper divisors (1950060813).

3250101315 is a wasteful number, since it uses less digits than its factorization.

3250101315 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 216673429.

The product of its (nonzero) digits is 450, while the sum is 21.

The square root of 3250101315 is about 57009.6598393641. The cubic root of 3250101315 is about 1481.2634261099.

Adding to 3250101315 its reverse (5131010523), we get a palindrome (8381111838).

The spelling of 3250101315 in words is "three billion, two hundred fifty million, one hundred one thousand, three hundred fifteen".

Divisors: 1 3 5 15 216673421 650020263 1083367105 3250101315