325031303130523 has 4 divisors (see below), whose sum is σ = 354579603415128. Its totient is φ = 295483002845920.

The previous prime is 325031303130511. The next prime is 325031303130533.

325031303130523 is nontrivially palindromic in base 10.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-325031303130523 is a prime.

It is a super-3 number, since 3×325031303130523³ (a number of 45 digits) contains 333 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (325031303130533) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 14774150142286 + ... + 14774150142307.

It is an arithmetic number, because the mean of its divisors is an integer number (88644900853782).

Almost surely, 2^{325031303130523} is an apocalyptic number.

325031303130523 is a deficient number, since it is larger than the sum of its proper divisors (29548300284605).

325031303130523 is a wasteful number, since it uses less digits than its factorization.

325031303130523 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 29548300284604.

The product of its (nonzero) digits is 72900, while the sum is 34.

It can be divided in two parts, 32503130 and 3130523, that added together give a palindrome (35633653).

The spelling of 325031303130523 in words is "three hundred twenty-five trillion, thirty-one billion, three hundred three million, one hundred thirty thousand, five hundred twenty-three".