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3250313540000 = 25542324159127
BaseRepresentation
bin101111010011000101110…
…010001011000110100000
3102111201121221100121120222
4233103011302023012200
5411223120231240000
610525101243222212
7453553541145452
oct57230562130640
912451557317528
103250313540000
1110434a529219a
12445b23517968
131a767084a807
14b345d2042d2
1559834d43a85
hex2f4c5c8b1a0

3250313540000 has 720 divisors, whose sum is σ = 8776618583040. Its totient is φ = 1183311360000.

The previous prime is 3250313539997. The next prime is 3250313540027. The reversal of 3250313540000 is 453130523.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 119 ways as a sum of consecutive naturals, for example, 25593019937 + ... + 25593020063.

It is an arithmetic number, because the mean of its divisors is an integer number (12189748032).

Almost surely, 23250313540000 is an apocalyptic number.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 3250313540000, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (4388309291520).

3250313540000 is an abundant number, since it is smaller than the sum of its proper divisors (5526305043040).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

3250313540000 is a wasteful number, since it uses less digits than its factorization.

3250313540000 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 303 (or 257 counting only the distinct ones).

The product of its (nonzero) digits is 5400, while the sum is 26.

Adding to 3250313540000 its reverse (453130523), we get a palindrome (3250766670523).

The spelling of 3250313540000 in words is "three trillion, two hundred fifty billion, three hundred thirteen million, five hundred forty thousand".