Base | Representation |
---|---|
bin | 1001011101100011010… |
… | …11011111000111000101 |
3 | 1011002011000121200010212 |
4 | 10232301223133013011 |
5 | 20311302444422203 |
6 | 405203412325205 |
7 | 32326240163063 |
oct | 4566153370705 |
9 | 1132130550125 |
10 | 325103514053 |
11 | 11596a504a2a |
12 | 53010613805 |
13 | 24870939236 |
14 | 11a41153033 |
15 | 86cb4cc1d8 |
hex | 4bb1adf1c5 |
325103514053 has 2 divisors, whose sum is σ = 325103514054. Its totient is φ = 325103514052.
The previous prime is 325103514017. The next prime is 325103514059. The reversal of 325103514053 is 350415301523.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 231055185124 + 94048328929 = 480682^2 + 306673^2 .
It is a cyclic number.
It is not a de Polignac number, because 325103514053 - 224 = 325086736837 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (325103514059) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 162551757026 + 162551757027.
It is an arithmetic number, because the mean of its divisors is an integer number (162551757027).
Almost surely, 2325103514053 is an apocalyptic number.
It is an amenable number.
325103514053 is a deficient number, since it is larger than the sum of its proper divisors (1).
325103514053 is an equidigital number, since it uses as much as digits as its factorization.
325103514053 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 27000, while the sum is 32.
Adding to 325103514053 its reverse (350415301523), we get a palindrome (675518815576).
The spelling of 325103514053 in words is "three hundred twenty-five billion, one hundred three million, five hundred fourteen thousand, fifty-three".
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