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325122111493 = 613353011921
BaseRepresentation
bin1001011101100101100…
…10011011100000000101
31011002012022121112000221
410232302302123200011
520311322230031433
6405205315104341
732326554231034
oct4566262334005
91132168545027
10325122111493
11115979a57513
12530168a20b1
132487474b13a
1411a437d471b
1586cce5272d
hex4bb2c9b805

325122111493 has 4 divisors (see below), whose sum is σ = 325175129548. Its totient is φ = 325069093440.

The previous prime is 325122111487. The next prime is 325122111511. The reversal of 325122111493 is 394111221523.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 264811101604 + 60311009889 = 514598^2 + 245583^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-325122111493 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (325122111473) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 26499828 + ... + 26512093.

It is an arithmetic number, because the mean of its divisors is an integer number (81293782387).

Almost surely, 2325122111493 is an apocalyptic number.

It is an amenable number.

325122111493 is a deficient number, since it is larger than the sum of its proper divisors (53018055).

325122111493 is an equidigital number, since it uses as much as digits as its factorization.

325122111493 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 53018054.

The product of its digits is 12960, while the sum is 34.

The spelling of 325122111493 in words is "three hundred twenty-five billion, one hundred twenty-two million, one hundred eleven thousand, four hundred ninety-three".

Divisors: 1 6133 53011921 325122111493