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32512350131 is a prime number
BaseRepresentation
bin11110010001111000…
…110001011110110011
310002220211201111211222
4132101320301132303
51013041130201011
622534100255255
72230454262542
oct362170613663
9102824644758
1032512350131
1112874412958
1263743a152b
1330b1a29a01
141805d92159
15ca4493ddb
hex791e317b3

32512350131 has 2 divisors, whose sum is σ = 32512350132. Its totient is φ = 32512350130.

The previous prime is 32512350083. The next prime is 32512350133. The reversal of 32512350131 is 13105321523.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 32512350131 - 26 = 32512350067 is a prime.

It is a super-2 number, since 2×325123501312 (a number of 22 digits) contains 22 as substring.

Together with 32512350133, it forms a pair of twin primes.

It is a Chen prime.

It is a self number, because there is not a number n which added to its sum of digits gives 32512350131.

It is not a weakly prime, because it can be changed into another prime (32512350133) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 16256175065 + 16256175066.

It is an arithmetic number, because the mean of its divisors is an integer number (16256175066).

Almost surely, 232512350131 is an apocalyptic number.

32512350131 is a deficient number, since it is larger than the sum of its proper divisors (1).

32512350131 is an equidigital number, since it uses as much as digits as its factorization.

32512350131 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 2700, while the sum is 26.

Adding to 32512350131 its reverse (13105321523), we get a palindrome (45617671654).

The spelling of 32512350131 in words is "thirty-two billion, five hundred twelve million, three hundred fifty thousand, one hundred thirty-one".