Base | Representation |
---|---|
bin | 10011011000010… |
… | …011111010000001 |
3 | 211122210211100211 |
4 | 103120103322001 |
5 | 1131213440342 |
6 | 52132514121 |
7 | 11025434212 |
oct | 2330237201 |
9 | 748724324 |
10 | 325140097 |
11 | 157595627 |
12 | 90a7b941 |
13 | 524909b9 |
14 | 31279409 |
15 | 1d827c17 |
hex | 13613e81 |
325140097 has 2 divisors, whose sum is σ = 325140098. Its totient is φ = 325140096.
The previous prime is 325140037. The next prime is 325140119. The reversal of 325140097 is 790041523.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 318122896 + 7017201 = 17836^2 + 2649^2 .
It is an emirp because it is prime and its reverse (790041523) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 325140097 - 211 = 325138049 is a prime.
It is a Chen prime.
It is not a weakly prime, because it can be changed into another prime (325140017) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (13) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 162570048 + 162570049.
It is an arithmetic number, because the mean of its divisors is an integer number (162570049).
Almost surely, 2325140097 is an apocalyptic number.
It is an amenable number.
325140097 is a deficient number, since it is larger than the sum of its proper divisors (1).
325140097 is an equidigital number, since it uses as much as digits as its factorization.
325140097 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 7560, while the sum is 31.
The square root of 325140097 is about 18031.6415503414. The cubic root of 325140097 is about 687.6332106391.
The spelling of 325140097 in words is "three hundred twenty-five million, one hundred forty thousand, ninety-seven".
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