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325141001 = 601154091
BaseRepresentation
bin10011011000010…
…100001000001001
3211122210212121022
4103120110020021
51131214003001
652132522225
711025436643
oct2330241011
9748725538
10325141001
11157596279
1290a80375
1352491233
1431279893
151d82811b
hex13614209

325141001 has 4 divisors (see below), whose sum is σ = 325201104. Its totient is φ = 325080900.

The previous prime is 325140983. The next prime is 325141009. The reversal of 325141001 is 100141523.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 100141523 = 977102499.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-325141001 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (325141009) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 21035 + ... + 33056.

It is an arithmetic number, because the mean of its divisors is an integer number (81300276).

Almost surely, 2325141001 is an apocalyptic number.

It is an amenable number.

325141001 is a deficient number, since it is larger than the sum of its proper divisors (60103).

325141001 is an equidigital number, since it uses as much as digits as its factorization.

325141001 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 60102.

The product of its (nonzero) digits is 120, while the sum is 17.

The square root of 325141001 is about 18031.6666173707. Note that the first 4 decimals coincide. The cubic root of 325141001 is about 687.6338479232.

Adding to 325141001 its reverse (100141523), we get a palindrome (425282524).

The spelling of 325141001 in words is "three hundred twenty-five million, one hundred forty-one thousand, one".

Divisors: 1 6011 54091 325141001