Search a number
-
+
325164927053 is a prime number
BaseRepresentation
bin1001011101101010101…
…01110000100001001101
31011002022022011202221102
410232311111300201031
520311414210131203
6405213444512445
732330614163531
oct4566525604115
91132268152842
10325164927053
111159a114047a
12530290ab725
132488058c3a5
1411a4937bbc1
1586d1aad888
hex4bb557084d

325164927053 has 2 divisors, whose sum is σ = 325164927054. Its totient is φ = 325164927052.

The previous prime is 325164927019. The next prime is 325164927083. The reversal of 325164927053 is 350729461523.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 241054486729 + 84110440324 = 490973^2 + 290018^2 .

It is a cyclic number.

It is not a de Polignac number, because 325164927053 - 210 = 325164926029 is a prime.

It is a super-2 number, since 2×3251649270532 (a number of 24 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 325164926989 and 325164927007.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (325164927083) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 162582463526 + 162582463527.

It is an arithmetic number, because the mean of its divisors is an integer number (162582463527).

Almost surely, 2325164927053 is an apocalyptic number.

It is an amenable number.

325164927053 is a deficient number, since it is larger than the sum of its proper divisors (1).

325164927053 is an equidigital number, since it uses as much as digits as its factorization.

325164927053 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1360800, while the sum is 47.

The spelling of 325164927053 in words is "three hundred twenty-five billion, one hundred sixty-four million, nine hundred twenty-seven thousand, fifty-three".