Base | Representation |
---|---|
bin | 101111010101000010001… |
… | …011011101100001000101 |
3 | 102111221000101102101121111 |
4 | 233111002023131201011 |
5 | 411241404014400223 |
6 | 10530044315045021 |
7 | 453656342323621 |
oct | 57250213354105 |
9 | 12457011371544 |
10 | 3252400543813 |
11 | 1044376354033 |
12 | 446406440771 |
13 | 1a7914038105 |
14 | b35ba46a181 |
15 | 5990819030d |
hex | 2f5422dd845 |
3252400543813 has 2 divisors, whose sum is σ = 3252400543814. Its totient is φ = 3252400543812.
The previous prime is 3252400543793. The next prime is 3252400543817. The reversal of 3252400543813 is 3183450042523.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 3097240970404 + 155159573409 = 1759898^2 + 393903^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-3252400543813 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (3252400543817) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1626200271906 + 1626200271907.
It is an arithmetic number, because the mean of its divisors is an integer number (1626200271907).
Almost surely, 23252400543813 is an apocalyptic number.
It is an amenable number.
3252400543813 is a deficient number, since it is larger than the sum of its proper divisors (1).
3252400543813 is an equidigital number, since it uses as much as digits as its factorization.
3252400543813 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 345600, while the sum is 40.
The spelling of 3252400543813 in words is "three trillion, two hundred fifty-two billion, four hundred million, five hundred forty-three thousand, eight hundred thirteen".
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