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32525052112433 is a prime number
BaseRepresentation
bin1110110010100110101000…
…01011010110111000110001
311021011100211210201111022202
413121103110023112320301
513230342301320044213
6153101445213112545
76564600053251406
oct731232413267061
9137140753644282
1032525052112433
11a3aa884a9a191
1237936a6188755
13151c13a0a264a
148063142d02ad
153b60b7e52b58
hex1d94d42d6e31

32525052112433 has 2 divisors, whose sum is σ = 32525052112434. Its totient is φ = 32525052112432.

The previous prime is 32525052112411. The next prime is 32525052112439. The reversal of 32525052112433 is 33421125052523.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 28633554167089 + 3891497945344 = 5351033^2 + 1972688^2 .

It is a cyclic number.

It is not a de Polignac number, because 32525052112433 - 28 = 32525052112177 is a prime.

It is not a weakly prime, because it can be changed into another prime (32525052112439) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 16262526056216 + 16262526056217.

It is an arithmetic number, because the mean of its divisors is an integer number (16262526056217).

Almost surely, 232525052112433 is an apocalyptic number.

It is an amenable number.

32525052112433 is a deficient number, since it is larger than the sum of its proper divisors (1).

32525052112433 is an equidigital number, since it uses as much as digits as its factorization.

32525052112433 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 216000, while the sum is 38.

Adding to 32525052112433 its reverse (33421125052523), we get a palindrome (65946177164956).

The spelling of 32525052112433 in words is "thirty-two trillion, five hundred twenty-five billion, fifty-two million, one hundred twelve thousand, four hundred thirty-three".