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325300050523 = 7138133650569
BaseRepresentation
bin1001011101111010110…
…01001101101001011011
31011002122201102202111101
410232331121031221123
520312203303104043
6405235113012231
732334144543520
oct4567531155133
91132581382441
10325300050523
11115a60441768
12530663b4077
13248a257cbc6
1411a5d2b3147
1586dd8a024d
hex4bbd64da5b

325300050523 has 8 divisors (see below), whose sum is σ = 372040701920. Its totient is φ = 278626703040.

The previous prime is 325300050521. The next prime is 325300050539. The reversal of 325300050523 is 325050003523.

It is a sphenic number, since it is the product of 3 distinct primes.

It is not a de Polignac number, because 325300050523 - 21 = 325300050521 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 325300050491 and 325300050500.

It is not an unprimeable number, because it can be changed into a prime (325300050521) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 16815618 + ... + 16834951.

It is an arithmetic number, because the mean of its divisors is an integer number (46505087740).

Almost surely, 2325300050523 is an apocalyptic number.

325300050523 is a deficient number, since it is larger than the sum of its proper divisors (46740651397).

325300050523 is a wasteful number, since it uses less digits than its factorization.

325300050523 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 33651957.

The product of its (nonzero) digits is 13500, while the sum is 28.

Subtracting from 325300050523 its reverse (325050003523), we obtain a cube (250047000 = 6303).

The spelling of 325300050523 in words is "three hundred twenty-five billion, three hundred million, fifty thousand, five hundred twenty-three".

Divisors: 1 7 1381 9667 33650569 235553983 46471435789 325300050523