Base | Representation |
---|---|
bin | 1110110010110110000100… |
… | …01101001111101111010110 |
3 | 11021012011020102212212010112 |
4 | 13121123002031033233112 |
5 | 13231011240140132100 |
6 | 153105335455123022 |
7 | 6565312335652604 |
oct | 731330215175726 |
9 | 137164212785115 |
10 | 32533340552150 |
11 | a403348665669 |
12 | 3795219b13472 |
13 | 151cb5b2c6749 |
14 | 80689cddc874 |
15 | 3b6400926b35 |
hex | 1d96c234fbd6 |
32533340552150 has 12 divisors (see below), whose sum is σ = 60512013427092. Its totient is φ = 13013336220840.
The previous prime is 32533340552147. The next prime is 32533340552177. The reversal of 32533340552150 is 5125504333523.
It is a junction number, because it is equal to n+sod(n) for n = 32533340552098 and 32533340552107.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 5 ways as a sum of consecutive naturals, for example, 325333405472 + ... + 325333405571.
It is an arithmetic number, because the mean of its divisors is an integer number (5042667785591).
Almost surely, 232533340552150 is an apocalyptic number.
32533340552150 is a deficient number, since it is larger than the sum of its proper divisors (27978672874942).
32533340552150 is a wasteful number, since it uses less digits than its factorization.
32533340552150 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 650666811055 (or 650666811050 counting only the distinct ones).
The product of its (nonzero) digits is 810000, while the sum is 41.
Adding to 32533340552150 its reverse (5125504333523), we get a palindrome (37658844885673).
The spelling of 32533340552150 in words is "thirty-two trillion, five hundred thirty-three billion, three hundred forty million, five hundred fifty-two thousand, one hundred fifty".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.157 sec. • engine limits •