Base | Representation |
---|---|
bin | 101111010110000100100… |
… | …011100000001010000111 |
3 | 102112000212222212001121111 |
4 | 233112010203200022013 |
5 | 411301144110023333 |
6 | 10530351015225451 |
7 | 454026053624563 |
oct | 57260443401207 |
9 | 12460788761544 |
10 | 3253514142343 |
11 | 1044897a070a3 |
12 | 446677378287 |
13 | 1a7a6096a55a |
14 | b36843086a3 |
15 | 59970d104cd |
hex | 2f5848e0287 |
3253514142343 has 4 divisors (see below), whose sum is σ = 3259735011208. Its totient is φ = 3247293273480.
The previous prime is 3253514142299. The next prime is 3253514142377. The reversal of 3253514142343 is 3432414153523.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 3253514142343 - 29 = 3253514141831 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 3253514142296 and 3253514142305.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (3253514242343) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3110433648 + ... + 3110434693.
It is an arithmetic number, because the mean of its divisors is an integer number (814933752802).
Almost surely, 23253514142343 is an apocalyptic number.
3253514142343 is a deficient number, since it is larger than the sum of its proper divisors (6220868865).
3253514142343 is an equidigital number, since it uses as much as digits as its factorization.
3253514142343 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 6220868864.
The product of its digits is 518400, while the sum is 40.
Adding to 3253514142343 its reverse (3432414153523), we get a palindrome (6685928295866).
The spelling of 3253514142343 in words is "three trillion, two hundred fifty-three billion, five hundred fourteen million, one hundred forty-two thousand, three hundred forty-three".
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