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3253541143 is a prime number
BaseRepresentation
bin1100000111101101…
…0001100100010111
322101202010000101211
43001323101210113
523130401304033
61254502402251
7143424433456
oct30173214427
98352100354
103253541143
11141a5a2686
12769730387
133cb096998
1422c164b9d
151409772cd
hexc1ed1917

3253541143 has 2 divisors, whose sum is σ = 3253541144. Its totient is φ = 3253541142.

The previous prime is 3253541131. The next prime is 3253541149. The reversal of 3253541143 is 3411453523.

3253541143 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It is an emirp because it is prime and its reverse (3411453523) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-3253541143 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (3253541149) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1626770571 + 1626770572.

It is an arithmetic number, because the mean of its divisors is an integer number (1626770572).

Almost surely, 23253541143 is an apocalyptic number.

3253541143 is a deficient number, since it is larger than the sum of its proper divisors (1).

3253541143 is an equidigital number, since it uses as much as digits as its factorization.

3253541143 is an evil number, because the sum of its binary digits is even.

The product of its digits is 21600, while the sum is 31.

The square root of 3253541143 is about 57039.8206781894. The cubic root of 3253541143 is about 1481.7858195569.

Adding to 3253541143 its reverse (3411453523), we get a palindrome (6664994666).

The spelling of 3253541143 in words is "three billion, two hundred fifty-three million, five hundred forty-one thousand, one hundred forty-three".