325365114703 has 4 divisors (see below), whose sum is σ = 325906488208. Its totient is φ = 324823741200.

The previous prime is 325365114689. The next prime is 325365114721. The reversal of 325365114703 is 307411563523.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 325365114703 - 2¹³ = 325365106511 is a prime.

It is a super-3 number, since 3×325365114703³ (a number of 36 digits) contains 333 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (325365114733) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 270685851 + ... + 270687052.

It is an arithmetic number, because the mean of its divisors is an integer number (81476622052).

Almost surely, 2^325365114703 is an apocalyptic number.

325365114703 is a deficient number, since it is larger than the sum of its proper divisors (541373505).

325365114703 is an equidigital number, since it uses as much as digits as its factorization.

325365114703 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 541373504.

The product of its (nonzero) digits is 226800, while the sum is 40.

The spelling of 325365114703 in words is "three hundred twenty-five billion, three hundred sixty-five million, one hundred fourteen thousand, seven hundred three".