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32540005213 = 70434620191
BaseRepresentation
bin11110010011100010…
…010001001101011101
310002222202202112111021
4132103202101031131
51013120220131323
622540525124141
72231241323602
oct362342211535
9102882675437
1032540005213
1112888a915a1
1263816b9651
1330b7690571
1418099106a9
15ca6b0805d
hex79389135d

32540005213 has 4 divisors (see below), whose sum is σ = 32544632448. Its totient is φ = 32535377980.

The previous prime is 32540005189. The next prime is 32540005217. The reversal of 32540005213 is 31250004523.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 31250004523 = 239130753157.

It is a cyclic number.

It is not a de Polignac number, because 32540005213 - 25 = 32540005181 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (32540005217) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2303053 + ... + 2317138.

It is an arithmetic number, because the mean of its divisors is an integer number (8136158112).

Almost surely, 232540005213 is an apocalyptic number.

It is an amenable number.

32540005213 is a deficient number, since it is larger than the sum of its proper divisors (4627235).

32540005213 is an equidigital number, since it uses as much as digits as its factorization.

32540005213 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 4627234.

The product of its (nonzero) digits is 3600, while the sum is 25.

Adding to 32540005213 its reverse (31250004523), we get a palindrome (63790009736).

The spelling of 32540005213 in words is "thirty-two billion, five hundred forty million, five thousand, two hundred thirteen".

Divisors: 1 7043 4620191 32540005213