Search a number
-
+
32540130533 = 131248397943
BaseRepresentation
bin11110010011100010…
…101111110011100101
310002222202222220101202
4132103202233303211
51013120233134113
622540531532245
72231242355141
oct362342576345
9102882886352
1032540130533
1112889067769
12638175a085
1330b7705611
141809944221
15ca6b30258
hex7938afce5

32540130533 has 4 divisors (see below), whose sum is σ = 32788528608. Its totient is φ = 32291732460.

The previous prime is 32540130529. The next prime is 32540130563. The reversal of 32540130533 is 33503104523.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 32540130533 - 22 = 32540130529 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 32540130496 and 32540130505.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (32540130523) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 124198841 + ... + 124199102.

It is an arithmetic number, because the mean of its divisors is an integer number (8197132152).

Almost surely, 232540130533 is an apocalyptic number.

It is an amenable number.

32540130533 is a deficient number, since it is larger than the sum of its proper divisors (248398075).

32540130533 is a wasteful number, since it uses less digits than its factorization.

32540130533 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 248398074.

The product of its (nonzero) digits is 16200, while the sum is 29.

The spelling of 32540130533 in words is "thirty-two billion, five hundred forty million, one hundred thirty thousand, five hundred thirty-three".

Divisors: 1 131 248397943 32540130533