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32540494241 is a prime number
BaseRepresentation
bin11110010011100100…
…001000100110100001
310002222210200101022102
4132103210020212201
51013120331303431
622540543420145
72231245431413
oct362344104641
9102883611272
1032540494241
1112889295a52
1263818b4655
1330b7802028
1418099da9b3
15ca6ba2dcb
hex7939089a1

32540494241 has 2 divisors, whose sum is σ = 32540494242. Its totient is φ = 32540494240.

The previous prime is 32540494183. The next prime is 32540494247. The reversal of 32540494241 is 14249404523.

It is a happy number.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 31638092641 + 902401600 = 177871^2 + 30040^2 .

It is an emirp because it is prime and its reverse (14249404523) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 32540494241 - 26 = 32540494177 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 32540494195 and 32540494204.

It is not a weakly prime, because it can be changed into another prime (32540494247) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 16270247120 + 16270247121.

It is an arithmetic number, because the mean of its divisors is an integer number (16270247121).

Almost surely, 232540494241 is an apocalyptic number.

It is an amenable number.

32540494241 is a deficient number, since it is larger than the sum of its proper divisors (1).

32540494241 is an equidigital number, since it uses as much as digits as its factorization.

32540494241 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 138240, while the sum is 38.

Adding to 32540494241 its reverse (14249404523), we get a palindrome (46789898764).

The spelling of 32540494241 in words is "thirty-two billion, five hundred forty million, four hundred ninety-four thousand, two hundred forty-one".