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32540502433 = 81234005971
BaseRepresentation
bin11110010011100100…
…001010100110100001
310002222210200210112211
4132103210022212201
51013120332034213
622540543522121
72231245464325
oct362344124641
9102883623484
1032540502433
11128892a111a
1263818b9341
1330b780598a
1418099dd985
15ca6ba553d
hex79390a9a1

32540502433 has 4 divisors (see below), whose sum is σ = 32544516528. Its totient is φ = 32536488340.

The previous prime is 32540502427. The next prime is 32540502457. The reversal of 32540502433 is 33420504523.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 32540502433 - 213 = 32540494241 is a prime.

It is a super-5 number, since 5×325405024335 (a number of 54 digits) contains 55555 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 32540502395 and 32540502404.

It is not an unprimeable number, because it can be changed into a prime (32540502413) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1994863 + ... + 2011108.

It is an arithmetic number, because the mean of its divisors is an integer number (8136129132).

Almost surely, 232540502433 is an apocalyptic number.

It is an amenable number.

32540502433 is a deficient number, since it is larger than the sum of its proper divisors (4014095).

32540502433 is an equidigital number, since it uses as much as digits as its factorization.

32540502433 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 4014094.

The product of its (nonzero) digits is 43200, while the sum is 31.

The spelling of 32540502433 in words is "thirty-two billion, five hundred forty million, five hundred two thousand, four hundred thirty-three".

Divisors: 1 8123 4005971 32540502433