Base | Representation |
---|---|
bin | 101111010110101010000… |
… | …111011010100001001101 |
3 | 102112002111220122001211001 |
4 | 233112222013122201031 |
5 | 411303441421012141 |
6 | 10530533330100301 |
7 | 454050505164211 |
oct | 57265207324115 |
9 | 12462456561731 |
10 | 3254144313421 |
11 | 10450906a1a41 |
12 | 44681241a691 |
13 | 1a7b3139ac51 |
14 | b3703ca6941 |
15 | 599ab2dca31 |
hex | 2f5aa1da84d |
3254144313421 has 2 divisors, whose sum is σ = 3254144313422. Its totient is φ = 3254144313420.
The previous prime is 3254144313383. The next prime is 3254144313443. The reversal of 3254144313421 is 1243134414523.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 2502056440521 + 752087872900 = 1581789^2 + 867230^2 .
It is a cyclic number.
It is not a de Polignac number, because 3254144313421 - 231 = 3251996829773 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (3254144313481) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1627072156710 + 1627072156711.
It is an arithmetic number, because the mean of its divisors is an integer number (1627072156711).
Almost surely, 23254144313421 is an apocalyptic number.
It is an amenable number.
3254144313421 is a deficient number, since it is larger than the sum of its proper divisors (1).
3254144313421 is an equidigital number, since it uses as much as digits as its factorization.
3254144313421 is an evil number, because the sum of its binary digits is even.
The product of its digits is 138240, while the sum is 37.
Adding to 3254144313421 its reverse (1243134414523), we get a palindrome (4497278727944).
The spelling of 3254144313421 in words is "three trillion, two hundred fifty-four billion, one hundred forty-four million, three hundred thirteen thousand, four hundred twenty-one".
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