Base | Representation |
---|---|
bin | 100100111111110101010001… |
… | …0110110100101000100011011 |
3 | 1120200021000220210101021001001 |
4 | 1021333222202312211010123 |
5 | 320123341030441001043 |
6 | 3112045325502205431 |
7 | 125355500231565115 |
oct | 11177524266450433 |
9 | 1520230823337031 |
10 | 325432404234523 |
11 | 94769120204423 |
12 | 305bab91883877 |
13 | 10c781b45c23c1 |
14 | 5a5102608a3b5 |
15 | 279539c54974d |
hex | 127faa2da511b |
325432404234523 has 4 divisors (see below), whose sum is σ = 328654507246848. Its totient is φ = 322210301222200.
The previous prime is 325432404234419. The next prime is 325432404234551.
325432404234523 is nontrivially palindromic in base 10.
It is a semiprime because it is the product of two primes.
It is not a de Polignac number, because 325432404234523 - 213 = 325432404226331 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (325432404234023) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1611051506011 + ... + 1611051506212.
It is an arithmetic number, because the mean of its divisors is an integer number (82163626811712).
Almost surely, 2325432404234523 is an apocalyptic number.
325432404234523 is a deficient number, since it is larger than the sum of its proper divisors (3222103012325).
325432404234523 is a wasteful number, since it uses less digits than its factorization.
325432404234523 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 3222103012324.
The product of its (nonzero) digits is 8294400, while the sum is 46.
It can be divided in two parts, 32543240 and 4234523, that added together give a palindrome (36777763).
The spelling of 325432404234523 in words is "three hundred twenty-five trillion, four hundred thirty-two billion, four hundred four million, two hundred thirty-four thousand, five hundred twenty-three".
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