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3254754013457 is a prime number
BaseRepresentation
bin101111010111001110011…
…101001111000100010001
3102112011002101220001000212
4233113032131033010101
5411311214011412312
610531114030053505
7454101560433302
oct57271635170421
912464071801025
103254754013457
111045373875671
1244696264a295
131a7bca7b19bb
14b3760c567a9
15599e4ac4822
hex2f5ce74f111

3254754013457 has 2 divisors, whose sum is σ = 3254754013458. Its totient is φ = 3254754013456.

The previous prime is 3254754013351. The next prime is 3254754013477. The reversal of 3254754013457 is 7543104574523.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 3254286113296 + 467900161 = 1803964^2 + 21631^2 .

It is a cyclic number.

It is not a de Polignac number, because 3254754013457 - 28 = 3254754013201 is a prime.

It is a super-2 number, since 2×32547540134572 (a number of 26 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (3254754013477) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1627377006728 + 1627377006729.

It is an arithmetic number, because the mean of its divisors is an integer number (1627377006729).

Almost surely, 23254754013457 is an apocalyptic number.

It is an amenable number.

3254754013457 is a deficient number, since it is larger than the sum of its proper divisors (1).

3254754013457 is an equidigital number, since it uses as much as digits as its factorization.

3254754013457 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 7056000, while the sum is 50.

The spelling of 3254754013457 in words is "three trillion, two hundred fifty-four billion, seven hundred fifty-four million, thirteen thousand, four hundred fifty-seven".