32565013401997 has 2 divisors, whose sum is σ = 32565013401998. Its totient is φ = 32565013401996.

The previous prime is 32565013401901. The next prime is 32565013402079. The reversal of 32565013401997 is 79910431056523.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 25492663548676 + 7072349853321 = 5049026^2 + 2659389^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-32565013401997 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (32565013402997) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 16282506700998 + 16282506700999.

It is an arithmetic number, because the mean of its divisors is an integer number (16282506700999).

Almost surely, 2^{32565013401997} is an apocalyptic number.

It is an amenable number.

32565013401997 is a deficient number, since it is larger than the sum of its proper divisors (1).

32565013401997 is an equidigital number, since it uses as much as digits as its factorization.

32565013401997 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 6123600, while the sum is 55.

The spelling of 32565013401997 in words is "thirty-two trillion, five hundred sixty-five billion, thirteen million, four hundred one thousand, nine hundred ninety-seven".