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32804949991241 is a prime number
BaseRepresentation
bin1110111010101111111110…
…11001000001111101001001
311022011010022100221221212202
413131113333121001331021
513244434014144204431
6153434215212045545
76624036146051531
oct735277731017511
9138133270857782
1032804949991241
11a4a855705728a
12381999b4638b5
13153c65531c48c
14815aa77664c1
153bd4ea9228cb
hex1dd5ff641f49

32804949991241 has 2 divisors, whose sum is σ = 32804949991242. Its totient is φ = 32804949991240.

The previous prime is 32804949991199. The next prime is 32804949991243. The reversal of 32804949991241 is 14219994940823.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 19527817302841 + 13277132688400 = 4419029^2 + 3643780^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-32804949991241 is a prime.

Together with 32804949991243, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (32804949991243) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 16402474995620 + 16402474995621.

It is an arithmetic number, because the mean of its divisors is an integer number (16402474995621).

Almost surely, 232804949991241 is an apocalyptic number.

It is an amenable number.

32804949991241 is a deficient number, since it is larger than the sum of its proper divisors (1).

32804949991241 is an equidigital number, since it uses as much as digits as its factorization.

32804949991241 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 40310784, while the sum is 65.

The spelling of 32804949991241 in words is "thirty-two trillion, eight hundred four billion, nine hundred forty-nine million, nine hundred ninety-one thousand, two hundred forty-one".