Base | Representation |
---|---|
bin | 1100001111001110… |
… | …0100100111010001 |
3 | 22110221110011200112 |
4 | 3003303210213101 |
5 | 23211434421213 |
6 | 1301550331105 |
7 | 144256455212 |
oct | 30363444721 |
9 | 8427404615 |
10 | 3285076433 |
11 | 1436381601 |
12 | 7781b9a95 |
13 | 404788712 |
14 | 232413409 |
15 | 143605ea8 |
hex | c3ce49d1 |
3285076433 has 2 divisors, whose sum is σ = 3285076434. Its totient is φ = 3285076432.
The previous prime is 3285076427. The next prime is 3285076439. The reversal of 3285076433 is 3346705823.
3285076433 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a balanced prime because it is at equal distance from previous prime (3285076427) and next prime (3285076439).
It can be written as a sum of positive squares in only one way, i.e., 1861749904 + 1423326529 = 43148^2 + 37727^2 .
It is a cyclic number.
It is not a de Polignac number, because 3285076433 - 212 = 3285072337 is a prime.
It is a Sophie Germain prime.
It is a Curzon number.
It is not a weakly prime, because it can be changed into another prime (3285076439) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1642538216 + 1642538217.
It is an arithmetic number, because the mean of its divisors is an integer number (1642538217).
Almost surely, 23285076433 is an apocalyptic number.
It is an amenable number.
3285076433 is a deficient number, since it is larger than the sum of its proper divisors (1).
3285076433 is an equidigital number, since it uses as much as digits as its factorization.
3285076433 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 362880, while the sum is 41.
The square root of 3285076433 is about 57315.5863007612. The cubic root of 3285076433 is about 1486.5578896853.
The spelling of 3285076433 in words is "three billion, two hundred eighty-five million, seventy-six thousand, four hundred thirty-three".
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