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330001211001109 is a prime number
BaseRepresentation
bin100101100001000100110010…
…0111101010000100100010101
31121021102210210210100120120011
41023002021210331100210111
5321223214440004013414
63125504244035240221
7126336541433413624
oct11302114475204425
91537383723316504
10330001211001109
119616a80055063a
1231018541a49071
1311219c996ba96b
145b6c2029776bb
15282414eae7dc4
hex12c2264f50915

330001211001109 has 2 divisors, whose sum is σ = 330001211001110. Its totient is φ = 330001211001108.

The previous prime is 330001211001073. The next prime is 330001211001221. The reversal of 330001211001109 is 901100112100033.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 326485942242084 + 3515268759025 = 18068922^2 + 1874905^2 .

It is a cyclic number.

It is not a de Polignac number, because 330001211001109 - 213 = 330001210992917 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 330001211001109.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (330001211001409) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 165000605500554 + 165000605500555.

It is an arithmetic number, because the mean of its divisors is an integer number (165000605500555).

Almost surely, 2330001211001109 is an apocalyptic number.

It is an amenable number.

330001211001109 is a deficient number, since it is larger than the sum of its proper divisors (1).

330001211001109 is an equidigital number, since it uses as much as digits as its factorization.

330001211001109 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 162, while the sum is 22.

The spelling of 330001211001109 in words is "three hundred thirty trillion, one billion, two hundred eleven million, one thousand, one hundred nine".