330004113252423 has 4 divisors (see below), whose sum is σ = 440005484336568. Its totient is φ = 220002742168280.

The previous prime is 330004113252413. The next prime is 330004113252461. The reversal of 330004113252423 is 324252311400033.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 330004113252423 - 2⁸ = 330004113252167 is a prime.

It is a super-3 number, since 3×330004113252423³ (a number of 45 digits) contains 333 as substring.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (330004113252403) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 55000685542068 + ... + 55000685542073.

It is an arithmetic number, because the mean of its divisors is an integer number (110001371084142).

Almost surely, 2^{330004113252423} is an apocalyptic number.

330004113252423 is a deficient number, since it is larger than the sum of its proper divisors (110001371084145).

330004113252423 is a wasteful number, since it uses less digits than its factorization.

330004113252423 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 110001371084144.

The product of its (nonzero) digits is 51840, while the sum is 33.

Adding to 330004113252423 its reverse (324252311400033), we get a palindrome (654256424652456).

The spelling of 330004113252423 in words is "three hundred thirty trillion, four billion, one hundred thirteen million, two hundred fifty-two thousand, four hundred twenty-three".