Base | Representation |
---|---|
bin | 1001100110101100011… |
… | …01010010101011110001 |
3 | 1011112211001112012112002 |
4 | 10303112031102223301 |
5 | 20401330344314441 |
6 | 411334411543345 |
7 | 32561662651244 |
oct | 4632615225361 |
9 | 1145731465462 |
10 | 330011323121 |
11 | 117a58874587 |
12 | 53b6015ab55 |
13 | 2517365987c |
14 | 11d88c9725b |
15 | 88b72c2b9b |
hex | 4cd6352af1 |
330011323121 has 4 divisors (see below), whose sum is σ = 330016512000. Its totient is φ = 330006134244.
The previous prime is 330011323091. The next prime is 330011323157. The reversal of 330011323121 is 121323110033.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 330011323121 - 222 = 330007128817 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 330011323093 and 330011323102.
It is not an unprimeable number, because it can be changed into a prime (330011325121) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2497841 + ... + 2626638.
It is an arithmetic number, because the mean of its divisors is an integer number (82504128000).
Almost surely, 2330011323121 is an apocalyptic number.
It is an amenable number.
330011323121 is a deficient number, since it is larger than the sum of its proper divisors (5188879).
330011323121 is an equidigital number, since it uses as much as digits as its factorization.
330011323121 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 5188878.
The product of its (nonzero) digits is 324, while the sum is 20.
Adding to 330011323121 its reverse (121323110033), we get a palindrome (451334433154).
The spelling of 330011323121 in words is "three hundred thirty billion, eleven million, three hundred twenty-three thousand, one hundred twenty-one".
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