33001200000011 has 4 divisors (see below), whose sum is σ = 33001543297392. Its totient is φ = 33000856702632.

The previous prime is 33001200000001. The next prime is 33001200000073. The reversal of 33001200000011 is 11000000210033.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 33001200000011 - 2⁶ = 33001199999947 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 33001199999938 and 33001200000001.

It is not an unprimeable number, because it can be changed into a prime (33001200000001) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 171504455 + ... + 171696768.

It is an arithmetic number, because the mean of its divisors is an integer number (8250385824348).

Almost surely, 2^{33001200000011} is an apocalyptic number.

33001200000011 is a deficient number, since it is larger than the sum of its proper divisors (343297381).

33001200000011 is an equidigital number, since it uses as much as digits as its factorization.

33001200000011 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 343297380.

The product of its (nonzero) digits is 18, while the sum is 11.

Adding to 33001200000011 its reverse (11000000210033), we get a palindrome (44001200210044).

The spelling of 33001200000011 in words is "thirty-three trillion, one billion, two hundred million, eleven", and thus it is an aban number.