Base | Representation |
---|---|
bin | 1001100110101100101… |
… | …00110101100110000011 |
3 | 1011112211012020200211102 |
4 | 10303112110311212003 |
5 | 20401331401113443 |
6 | 411334522205015 |
7 | 32562015530102 |
oct | 4632624654603 |
9 | 1145735220742 |
10 | 330013301123 |
11 | 117a599a56a0 |
12 | 53b6095376b |
13 | 25173b9cc9c |
14 | 11d89250039 |
15 | 88b7563cb8 |
hex | 4cd6535983 |
330013301123 has 4 divisors (see below), whose sum is σ = 360014510328. Its totient is φ = 300012091920.
The previous prime is 330013301089. The next prime is 330013301141. The reversal of 330013301123 is 321103310033.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 330013301123 - 232 = 325718333827 is a prime.
It is a super-4 number, since 4×3300133011234 (a number of 47 digits) contains 4444 as substring. Note that it is a super-d number also for d = 2.
It is a junction number, because it is equal to n+sod(n) for n = 330013301095 and 330013301104.
It is not an unprimeable number, because it can be changed into a prime (330013301143) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 15000604586 + ... + 15000604607.
It is an arithmetic number, because the mean of its divisors is an integer number (90003627582).
Almost surely, 2330013301123 is an apocalyptic number.
330013301123 is a deficient number, since it is larger than the sum of its proper divisors (30001209205).
330013301123 is a wasteful number, since it uses less digits than its factorization.
330013301123 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 30001209204.
The product of its (nonzero) digits is 486, while the sum is 20.
Adding to 330013301123 its reverse (321103310033), we get a palindrome (651116611156).
It can be divided in two parts, 330013 and 301123, that added together give a palindrome (631136).
The spelling of 330013301123 in words is "three hundred thirty billion, thirteen million, three hundred one thousand, one hundred twenty-three".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.111 sec. • engine limits •