Base | Representation |
---|---|
bin | 100101100001010010101011… |
… | …0011100001110010100101011 |
3 | 1121021112122210002021000201221 |
4 | 1023002211112130032110223 |
5 | 321224212023222344321 |
6 | 3125530055123522511 |
7 | 126341645432606503 |
oct | 11302452634162453 |
9 | 1537478702230657 |
10 | 330031032231211 |
11 | 96181413892153 |
12 | 31022284b29437 |
13 | 1121ca3ca1ca4c |
14 | 5b6d831368a03 |
15 | 2824ce7bace41 |
hex | 12c295670e52b |
330031032231211 has 2 divisors, whose sum is σ = 330031032231212. Its totient is φ = 330031032231210.
The previous prime is 330031032231143. The next prime is 330031032231239. The reversal of 330031032231211 is 112132230130033.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 330031032231211 - 227 = 330030898013483 is a prime.
It is not a weakly prime, because it can be changed into another prime (330031032232211) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 165015516115605 + 165015516115606.
It is an arithmetic number, because the mean of its divisors is an integer number (165015516115606).
Almost surely, 2330031032231211 is an apocalyptic number.
330031032231211 is a deficient number, since it is larger than the sum of its proper divisors (1).
330031032231211 is an equidigital number, since it uses as much as digits as its factorization.
330031032231211 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1944, while the sum is 25.
Adding to 330031032231211 its reverse (112132230130033), we get a palindrome (442163262361244).
The spelling of 330031032231211 in words is "three hundred thirty trillion, thirty-one billion, thirty-two million, two hundred thirty-one thousand, two hundred eleven".
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