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3300344142113 = 5955938036307
BaseRepresentation
bin110000000001101011110…
…101110001100100100001
3102200111202122202112102102
4300001223311301210201
5413033101100021423
611004053540500145
7460304414225264
oct60015365614441
912614678675372
103300344142113
111062739257047
124537666aa655
131ac2b4a435a5
14b5a47a1ccdb
155acb2230c28
hex3006bd71921

3300344142113 has 4 divisors (see below), whose sum is σ = 3356282178480. Its totient is φ = 3244406105748.

The previous prime is 3300344142047. The next prime is 3300344142119. The reversal of 3300344142113 is 3112414430033.

It is a happy number.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 3300344142113 - 216 = 3300344076577 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (3300344142119) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 27969018095 + ... + 27969018212.

It is an arithmetic number, because the mean of its divisors is an integer number (839070544620).

Almost surely, 23300344142113 is an apocalyptic number.

It is an amenable number.

3300344142113 is a deficient number, since it is larger than the sum of its proper divisors (55938036367).

3300344142113 is an equidigital number, since it uses as much as digits as its factorization.

3300344142113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 55938036366.

The product of its (nonzero) digits is 10368, while the sum is 29.

Adding to 3300344142113 its reverse (3112414430033), we get a palindrome (6412758572146).

The spelling of 3300344142113 in words is "three trillion, three hundred billion, three hundred forty-four million, one hundred forty-two thousand, one hundred thirteen".

Divisors: 1 59 55938036307 3300344142113