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330041143234147 is a prime number
BaseRepresentation
bin100101100001010111011000…
…1000110101000111001100011
31121021120121212201220012021011
41023002232301012220321203
5321224343230131443042
63125534450313441351
7126342454125661252
oct11302566106507143
91537517781805234
10330041143234147
1196185732223324
1231024227110257
1311220991703c17
145b70110144799
1528251da695a17
hex12c2bb11a8e63

330041143234147 has 2 divisors, whose sum is σ = 330041143234148. Its totient is φ = 330041143234146.

The previous prime is 330041143234069. The next prime is 330041143234157. The reversal of 330041143234147 is 741432341140033.

It is a strong prime.

It is an emirp because it is prime and its reverse (741432341140033) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-330041143234147 is a prime.

It is not a weakly prime, because it can be changed into another prime (330041143234157) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 165020571617073 + 165020571617074.

It is an arithmetic number, because the mean of its divisors is an integer number (165020571617074).

Almost surely, 2330041143234147 is an apocalyptic number.

330041143234147 is a deficient number, since it is larger than the sum of its proper divisors (1).

330041143234147 is an equidigital number, since it uses as much as digits as its factorization.

330041143234147 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 290304, while the sum is 40.

The spelling of 330041143234147 in words is "three hundred thirty trillion, forty-one billion, one hundred forty-three million, two hundred thirty-four thousand, one hundred forty-seven".