Base | Representation |
---|---|
bin | 100101100001110010111001… |
… | …0111101100100111000011111 |
3 | 1121021210021101121110201122221 |
4 | 1023003211302331210320133 |
5 | 321231330232413310101 |
6 | 3130021541404450211 |
7 | 126346645301006206 |
oct | 11303456275447037 |
9 | 1537707347421587 |
10 | 330100230213151 |
11 | 961a87a3295182 |
12 | 31033777249967 |
13 | 11226419c58aa8 |
14 | 5b72d1764c23d |
15 | 28269e7b98aa1 |
hex | 12c3972f64e1f |
330100230213151 has 2 divisors, whose sum is σ = 330100230213152. Its totient is φ = 330100230213150.
The previous prime is 330100230213119. The next prime is 330100230213181. The reversal of 330100230213151 is 151312032001033.
It is a strong prime.
It is an emirp because it is prime and its reverse (151312032001033) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 330100230213151 - 25 = 330100230213119 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (330100230213181) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 165050115106575 + 165050115106576.
It is an arithmetic number, because the mean of its divisors is an integer number (165050115106576).
Almost surely, 2330100230213151 is an apocalyptic number.
330100230213151 is a deficient number, since it is larger than the sum of its proper divisors (1).
330100230213151 is an equidigital number, since it uses as much as digits as its factorization.
330100230213151 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1620, while the sum is 25.
Adding to 330100230213151 its reverse (151312032001033), we get a palindrome (481412262214184).
The spelling of 330100230213151 in words is "three hundred thirty trillion, one hundred billion, two hundred thirty million, two hundred thirteen thousand, one hundred fifty-one".
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