3301004011 has 4 divisors (see below), whose sum is σ = 3307106224. Its totient is φ = 3294901800.

The previous prime is 3301003991. The next prime is 3301004023. The reversal of 3301004011 is 1104001033.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 1104001033 = 1213 ⋅910141.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-3301004011 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 3301003982 and 3301004000.

It is not an unprimeable number, because it can be changed into a prime (3301004041) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3050295 + ... + 3051376.

It is an arithmetic number, because the mean of its divisors is an integer number (826776556).

Almost surely, 2^3301004011 is an apocalyptic number.

3301004011 is a deficient number, since it is larger than the sum of its proper divisors (6102213).

3301004011 is an equidigital number, since it uses as much as digits as its factorization.

3301004011 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 6102212.

The product of its (nonzero) digits is 36, while the sum is 13.

The square root of 3301004011 is about 57454.3645948678. The cubic root of 3301004011 is about 1488.9565252351.

Adding to 3301004011 its reverse (1104001033), we get a palindrome (4405005044).

The spelling of 3301004011 in words is "three billion, three hundred one million, four thousand, eleven".