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330113130093917 is a prime number
BaseRepresentation
bin100101100001111000111001…
…1110110101101110101011101
31121021211111200121212120100122
41023003301303312231311131
5321232033142301001132
63130031513422004325
7126350613050124062
oct11303616366556535
91537744617776318
10330113130093917
11962032129a7565
12310361774166a5
13112276c4674931
145b737bc994c69
152827000420912
hex12c3c73dadd5d

330113130093917 has 2 divisors, whose sum is σ = 330113130093918. Its totient is φ = 330113130093916.

The previous prime is 330113130093907. The next prime is 330113130094079. The reversal of 330113130093917 is 719390031311033.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 209323776336676 + 120789353757241 = 14468026^2 + 10990421^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-330113130093917 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (330113130093907) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (29) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 165056565046958 + 165056565046959.

It is an arithmetic number, because the mean of its divisors is an integer number (165056565046959).

Almost surely, 2330113130093917 is an apocalyptic number.

It is an amenable number.

330113130093917 is a deficient number, since it is larger than the sum of its proper divisors (1).

330113130093917 is an equidigital number, since it uses as much as digits as its factorization.

330113130093917 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 137781, while the sum is 44.

The spelling of 330113130093917 in words is "three hundred thirty trillion, one hundred thirteen billion, one hundred thirty million, ninety-three thousand, nine hundred seventeen".