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3301201212103 = 5955952562917
BaseRepresentation
bin110000000010011110111…
…011001111001011000111
3102200120222101111012102101
4300002132323033023013
5413041330002241403
611004314554452531
7460334562213514
oct60023673171307
912616871435371
103301201212103
111063039027453
12453965734147
131ac3c04888b2
14b5ac97a230b
155ad125cc71d
hex3009eecf2c7

3301201212103 has 4 divisors (see below), whose sum is σ = 3357153775080. Its totient is φ = 3245248649128.

The previous prime is 3301201212091. The next prime is 3301201212131. The reversal of 3301201212103 is 3012121021033.

It is a semiprime because it is the product of two primes.

It is a de Polignac number, because none of the positive numbers 2k-3301201212103 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (3301201212163) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 27976281400 + ... + 27976281517.

It is an arithmetic number, because the mean of its divisors is an integer number (839288443770).

Almost surely, 23301201212103 is an apocalyptic number.

3301201212103 is a deficient number, since it is larger than the sum of its proper divisors (55952562977).

3301201212103 is an equidigital number, since it uses as much as digits as its factorization.

3301201212103 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 55952562976.

The product of its (nonzero) digits is 216, while the sum is 19.

Adding to 3301201212103 its reverse (3012121021033), we get a palindrome (6313322233136).

The spelling of 3301201212103 in words is "three trillion, three hundred one billion, two hundred one million, two hundred twelve thousand, one hundred three".

Divisors: 1 59 55952562917 3301201212103