Base | Representation |
---|---|
bin | 1111000000110101011011… |
… | …10010111010101100100010 |
3 | 11022220002222211020121110222 |
4 | 13200122231302322230202 |
5 | 13311400220304134132 |
6 | 154114234341323042 |
7 | 6645120356424002 |
oct | 740325562725442 |
9 | 138802884217428 |
10 | 33014034443042 |
11 | a57919a850594 |
12 | 3852411406482 |
13 | 155629674a403 |
14 | 821c60164002 |
15 | 3c3b866a6412 |
hex | 1e06adcbab22 |
33014034443042 has 4 divisors (see below), whose sum is σ = 49521051664566. Its totient is φ = 16507017221520.
The previous prime is 33014034443041. The next prime is 33014034443107. The reversal of 33014034443042 is 24034443041033.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in only one way, i.e., 32896063489081 + 117970953961 = 5735509^2 + 343469^2 .
It is a junction number, because it is equal to n+sod(n) for n = 33014034442993 and 33014034443011.
It is not an unprimeable number, because it can be changed into a prime (33014034443041) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 8253508610759 + ... + 8253508610762.
Almost surely, 233014034443042 is an apocalyptic number.
33014034443042 is a deficient number, since it is larger than the sum of its proper divisors (16507017221524).
33014034443042 is a wasteful number, since it uses less digits than its factorization.
33014034443042 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 16507017221523.
The product of its (nonzero) digits is 165888, while the sum is 35.
Adding to 33014034443042 its reverse (24034443041033), we get a palindrome (57048477484075).
The spelling of 33014034443042 in words is "thirty-three trillion, fourteen billion, thirty-four million, four hundred forty-three thousand, forty-two".
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