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33014034443042 = 216507017221521
BaseRepresentation
bin1111000000110101011011…
…10010111010101100100010
311022220002222211020121110222
413200122231302322230202
513311400220304134132
6154114234341323042
76645120356424002
oct740325562725442
9138802884217428
1033014034443042
11a57919a850594
123852411406482
13155629674a403
14821c60164002
153c3b866a6412
hex1e06adcbab22

33014034443042 has 4 divisors (see below), whose sum is σ = 49521051664566. Its totient is φ = 16507017221520.

The previous prime is 33014034443041. The next prime is 33014034443107. The reversal of 33014034443042 is 24034443041033.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in only one way, i.e., 32896063489081 + 117970953961 = 5735509^2 + 343469^2 .

It is a junction number, because it is equal to n+sod(n) for n = 33014034442993 and 33014034443011.

It is not an unprimeable number, because it can be changed into a prime (33014034443041) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 8253508610759 + ... + 8253508610762.

Almost surely, 233014034443042 is an apocalyptic number.

33014034443042 is a deficient number, since it is larger than the sum of its proper divisors (16507017221524).

33014034443042 is a wasteful number, since it uses less digits than its factorization.

33014034443042 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 16507017221523.

The product of its (nonzero) digits is 165888, while the sum is 35.

Adding to 33014034443042 its reverse (24034443041033), we get a palindrome (57048477484075).

The spelling of 33014034443042 in words is "thirty-three trillion, fourteen billion, thirty-four million, four hundred forty-three thousand, forty-two".

Divisors: 1 2 16507017221521 33014034443042