Base | Representation |
---|---|
bin | 110000000010101101111… |
… | …000011111010101100010 |
3 | 102200121121212200011122210 |
4 | 300002231320133111202 |
5 | 413042333222300424 |
6 | 11004355521142550 |
7 | 460344030153306 |
oct | 60025570372542 |
9 | 12617555604583 |
10 | 3301452150114 |
11 | 1063157740938 |
12 | 453a1578aa56 |
13 | 1ac430469221 |
14 | b5b10c43d06 |
15 | 5ad29649729 |
hex | 300ade1f562 |
3301452150114 has 8 divisors (see below), whose sum is σ = 6602904300240. Its totient is φ = 1100484050036.
The previous prime is 3301452150103. The next prime is 3301452150133. The reversal of 3301452150114 is 4110512541033.
It is a sphenic number, since it is the product of 3 distinct primes.
3301452150114 is an admirable number.
It is a super-3 number, since 3×33014521501143 (a number of 39 digits) contains 333 as substring.
It is a Curzon number.
It is an unprimeable number.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 275121012504 + ... + 275121012515.
It is an arithmetic number, because the mean of its divisors is an integer number (825363037530).
Almost surely, 23301452150114 is an apocalyptic number.
3301452150114 is a primitive abundant number, since it is smaller than the sum of its proper divisors, none of which is abundant.
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
3301452150114 is a wasteful number, since it uses less digits than its factorization.
3301452150114 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 550242025024.
The product of its (nonzero) digits is 7200, while the sum is 30.
Adding to 3301452150114 its reverse (4110512541033), we get a palindrome (7411964691147).
The spelling of 3301452150114 in words is "three trillion, three hundred one billion, four hundred fifty-two million, one hundred fifty thousand, one hundred fourteen".
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