Base | Representation |
---|---|
bin | 1001100111000010111… |
… | …01011101100011101101 |
3 | 1011120022012202122021101 |
4 | 10303201131131203231 |
5 | 20402222212030331 |
6 | 411405234203101 |
7 | 32566444431232 |
oct | 4634135354355 |
9 | 1146265678241 |
10 | 330200111341 |
11 | 118045399a01 |
12 | 53bb3423491 |
13 | 251a37b9889 |
14 | 11da5d9b789 |
15 | 88c8b65061 |
hex | 4ce175d8ed |
330200111341 has 4 divisors (see below), whose sum is σ = 330283773792. Its totient is φ = 330116448892.
The previous prime is 330200111273. The next prime is 330200111377. The reversal of 330200111341 is 143111002033.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 330200111341 - 217 = 330199980269 is a prime.
It is a super-2 number, since 2×3302001113412 (a number of 24 digits) contains 22 as substring.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (330200114341) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 41825305 + ... + 41833198.
It is an arithmetic number, because the mean of its divisors is an integer number (82570943448).
Almost surely, 2330200111341 is an apocalyptic number.
It is an amenable number.
330200111341 is a deficient number, since it is larger than the sum of its proper divisors (83662451).
330200111341 is an equidigital number, since it uses as much as digits as its factorization.
330200111341 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 83662450.
The product of its (nonzero) digits is 216, while the sum is 19.
Adding to 330200111341 its reverse (143111002033), we get a palindrome (473311113374).
The spelling of 330200111341 in words is "three hundred thirty billion, two hundred million, one hundred eleven thousand, three hundred forty-one".
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