Base | Representation |
---|---|
bin | 11110110000001101… |
… | …000111100101101001 |
3 | 10011020021211121100112 |
4 | 132300031013211221 |
5 | 1020111334000131 |
6 | 23100350344105 |
7 | 2246201604101 |
oct | 366015074551 |
9 | 104207747315 |
10 | 33021000041 |
11 | 13005548087 |
12 | 64967bb035 |
13 | 316321cca3 |
14 | 185375a201 |
15 | cd3e6a02b |
hex | 7b0347969 |
33021000041 has 2 divisors, whose sum is σ = 33021000042. Its totient is φ = 33021000040.
The previous prime is 33021000031. The next prime is 33021000071. The reversal of 33021000041 is 14000012033.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 25224110041 + 7796890000 = 158821^2 + 88300^2 .
It is a cyclic number.
It is not a de Polignac number, because 33021000041 - 214 = 33020983657 is a prime.
It is not a weakly prime, because it can be changed into another prime (33021000031) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 16510500020 + 16510500021.
It is an arithmetic number, because the mean of its divisors is an integer number (16510500021).
Almost surely, 233021000041 is an apocalyptic number.
It is an amenable number.
33021000041 is a deficient number, since it is larger than the sum of its proper divisors (1).
33021000041 is an equidigital number, since it uses as much as digits as its factorization.
33021000041 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 72, while the sum is 14.
Adding to 33021000041 its reverse (14000012033), we get a palindrome (47021012074).
The spelling of 33021000041 in words is "thirty-three billion, twenty-one million, forty-one", and thus it is an aban number and an uban number.
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