Base | Representation |
---|---|
bin | 11110110001011101… |
… | …010001101110111101 |
3 | 10011021202101011212121 |
4 | 132301131101232331 |
5 | 1020132223404432 |
6 | 23102421002541 |
7 | 2246545322521 |
oct | 366135215675 |
9 | 104252334777 |
10 | 33042013117 |
11 | 1301639a563 |
12 | 64a1853451 |
13 | 3167699569 |
14 | 1856469d81 |
15 | cd5c1b197 |
hex | 7b1751bbd |
33042013117 has 2 divisors, whose sum is σ = 33042013118. Its totient is φ = 33042013116.
The previous prime is 33042013111. The next prime is 33042013163. The reversal of 33042013117 is 71131024033.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 25036416441 + 8005596676 = 158229^2 + 89474^2 .
It is a cyclic number.
It is not a de Polignac number, because 33042013117 - 27 = 33042012989 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 33042013091 and 33042013100.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (33042013111) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 16521006558 + 16521006559.
It is an arithmetic number, because the mean of its divisors is an integer number (16521006559).
Almost surely, 233042013117 is an apocalyptic number.
It is an amenable number.
33042013117 is a deficient number, since it is larger than the sum of its proper divisors (1).
33042013117 is an equidigital number, since it uses as much as digits as its factorization.
33042013117 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1512, while the sum is 25.
The spelling of 33042013117 in words is "thirty-three billion, forty-two million, thirteen thousand, one hundred seventeen".
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