Base | Representation |
---|---|
bin | 11110110001111000… |
… | …110101111001101101 |
3 | 10011022020222022010102 |
4 | 132301320311321231 |
5 | 1020141101123044 |
6 | 23103235520445 |
7 | 2246663616623 |
oct | 366170657155 |
9 | 104266868112 |
10 | 33049239149 |
11 | 1301a485593 |
12 | 64a4159125 |
13 | 3169029614 |
14 | 18573cb513 |
15 | cd669724e |
hex | 7b1e35e6d |
33049239149 has 2 divisors, whose sum is σ = 33049239150. Its totient is φ = 33049239148.
The previous prime is 33049239109. The next prime is 33049239163. The reversal of 33049239149 is 94193294033.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 30903882025 + 2145357124 = 175795^2 + 46318^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-33049239149 is a prime.
It is a super-3 number, since 3×330492391493 (a number of 33 digits) contains 333 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (33049239109) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 16524619574 + 16524619575.
It is an arithmetic number, because the mean of its divisors is an integer number (16524619575).
Almost surely, 233049239149 is an apocalyptic number.
It is an amenable number.
33049239149 is a deficient number, since it is larger than the sum of its proper divisors (1).
33049239149 is an equidigital number, since it uses as much as digits as its factorization.
33049239149 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 629856, while the sum is 47.
The spelling of 33049239149 in words is "thirty-three billion, forty-nine million, two hundred thirty-nine thousand, one hundred forty-nine".
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