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3305040103 = 12372671819
BaseRepresentation
bin1100010011111110…
…1110100011100111
322112100000102200201
43010333232203213
523232042240403
61303542251331
7144621243301
oct30477564347
98470012621
103305040103
111446677602
12782a26b47
13408958441
14234d2c971
1514524b21d
hexc4fee8e7

3305040103 has 4 divisors (see below), whose sum is σ = 3307713160. Its totient is φ = 3302367048.

The previous prime is 3305040097. The next prime is 3305040143. The reversal of 3305040103 is 3010405033.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-3305040103 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (3305040143) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1334673 + ... + 1337146.

It is an arithmetic number, because the mean of its divisors is an integer number (826928290).

Almost surely, 23305040103 is an apocalyptic number.

3305040103 is a deficient number, since it is larger than the sum of its proper divisors (2673057).

3305040103 is a wasteful number, since it uses less digits than its factorization.

3305040103 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 2673056.

The product of its (nonzero) digits is 540, while the sum is 19.

The square root of 3305040103 is about 57489.4781938400. The cubic root of 3305040103 is about 1489.5631202681.

Adding to 3305040103 its reverse (3010405033), we get a palindrome (6315445136).

It can be divided in two parts, 33050 and 40103, that added together give a triangular number (73153 = T382).

The spelling of 3305040103 in words is "three billion, three hundred five million, forty thousand, one hundred three".

Divisors: 1 1237 2671819 3305040103