Base | Representation |
---|---|
bin | 11110110010000011… |
… | …100100001011000001 |
3 | 10011022110021010001012 |
4 | 132302003210023001 |
5 | 1020142311100423 |
6 | 23103420050305 |
7 | 2250026535065 |
oct | 366203441301 |
9 | 104273233035 |
10 | 33052050113 |
11 | 130210254a5 |
12 | 64a5093995 |
13 | 31697a1c04 |
14 | 185791daa5 |
15 | cd6a50078 |
hex | 7b20e42c1 |
33052050113 has 4 divisors (see below), whose sum is σ = 33052493760. Its totient is φ = 33051606468.
The previous prime is 33052050043. The next prime is 33052050133. The reversal of 33052050113 is 31105025033.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 31105025033 = 397 ⋅78350189.
It is a cyclic number.
It is not a de Polignac number, because 33052050113 - 216 = 33051984577 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (33052050133) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 79733 + ... + 269186.
It is an arithmetic number, because the mean of its divisors is an integer number (8263123440).
Almost surely, 233052050113 is an apocalyptic number.
It is an amenable number.
33052050113 is a deficient number, since it is larger than the sum of its proper divisors (443647).
33052050113 is an equidigital number, since it uses as much as digits as its factorization.
33052050113 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 443646.
The product of its (nonzero) digits is 1350, while the sum is 23.
Adding to 33052050113 its reverse (31105025033), we get a palindrome (64157075146).
The spelling of 33052050113 in words is "thirty-three billion, fifty-two million, fifty thousand, one hundred thirteen".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.078 sec. • engine limits •