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33052111441 = 80934084037
BaseRepresentation
bin11110110010000011…
…110011001001010001
310011022110101020011121
4132302003303021101
51020142320031231
623103421242241
72250030211636
oct366203631121
9104273336147
1033052111441
1113021067588
1264a5103381
1331697c3abb
14185793818d
15cd6a63311
hex7b20f3251

33052111441 has 4 divisors (see below), whose sum is σ = 33056203572. Its totient is φ = 33048019312.

The previous prime is 33052111439. The next prime is 33052111451. The reversal of 33052111441 is 14411125033.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 4725875025 + 28326236416 = 68745^2 + 168304^2 .

It is a cyclic number.

It is not a de Polignac number, because 33052111441 - 21 = 33052111439 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (33052111451) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2033926 + ... + 2050111.

It is an arithmetic number, because the mean of its divisors is an integer number (8264050893).

Almost surely, 233052111441 is an apocalyptic number.

It is an amenable number.

33052111441 is a deficient number, since it is larger than the sum of its proper divisors (4092131).

33052111441 is an equidigital number, since it uses as much as digits as its factorization.

33052111441 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 4092130.

The product of its (nonzero) digits is 1440, while the sum is 25.

Adding to 33052111441 its reverse (14411125033), we get a palindrome (47463236474).

The spelling of 33052111441 in words is "thirty-three billion, fifty-two million, one hundred eleven thousand, four hundred forty-one".

Divisors: 1 8093 4084037 33052111441